Optimal. Leaf size=89 \[ \frac{d (c+d x) \sin (a+b x) \cos (a+b x)}{2 b^2}-\frac{d^2 \sin ^2(a+b x)}{4 b^3}+\frac{(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac{c d x}{2 b}-\frac{d^2 x^2}{4 b} \]
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Rubi [A] time = 0.0541044, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1, Rules used = {4404, 3310} \[ \frac{d (c+d x) \sin (a+b x) \cos (a+b x)}{2 b^2}-\frac{d^2 \sin ^2(a+b x)}{4 b^3}+\frac{(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac{c d x}{2 b}-\frac{d^2 x^2}{4 b} \]
Antiderivative was successfully verified.
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Rule 4404
Rule 3310
Rubi steps
\begin{align*} \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx &=\frac{(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac{d \int (c+d x) \sin ^2(a+b x) \, dx}{b}\\ &=\frac{d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac{d^2 \sin ^2(a+b x)}{4 b^3}+\frac{(c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac{d \int (c+d x) \, dx}{2 b}\\ &=-\frac{c d x}{2 b}-\frac{d^2 x^2}{4 b}+\frac{d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac{d^2 \sin ^2(a+b x)}{4 b^3}+\frac{(c+d x)^2 \sin ^2(a+b x)}{2 b}\\ \end{align*}
Mathematica [A] time = 0.233082, size = 50, normalized size = 0.56 \[ \frac{\cos (2 (a+b x)) \left (d^2-2 b^2 (c+d x)^2\right )+2 b d (c+d x) \sin (2 (a+b x))}{8 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.015, size = 215, normalized size = 2.4 \begin{align*}{\frac{1}{b} \left ({\frac{{d}^{2}}{{b}^{2}} \left ( -{\frac{ \left ( bx+a \right ) ^{2} \left ( \cos \left ( bx+a \right ) \right ) ^{2}}{2}}+ \left ( bx+a \right ) \left ({\frac{\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) }{2}}+{\frac{bx}{2}}+{\frac{a}{2}} \right ) -{\frac{ \left ( bx+a \right ) ^{2}}{4}}-{\frac{ \left ( \sin \left ( bx+a \right ) \right ) ^{2}}{4}} \right ) }-2\,{\frac{a{d}^{2} \left ( -1/2\, \left ( bx+a \right ) \left ( \cos \left ( bx+a \right ) \right ) ^{2}+1/4\,\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) +1/4\,bx+a/4 \right ) }{{b}^{2}}}+2\,{\frac{cd \left ( -1/2\, \left ( bx+a \right ) \left ( \cos \left ( bx+a \right ) \right ) ^{2}+1/4\,\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) +1/4\,bx+a/4 \right ) }{b}}-{\frac{{a}^{2}{d}^{2} \left ( \cos \left ( bx+a \right ) \right ) ^{2}}{2\,{b}^{2}}}+{\frac{acd \left ( \cos \left ( bx+a \right ) \right ) ^{2}}{b}}-{\frac{{c}^{2} \left ( \cos \left ( bx+a \right ) \right ) ^{2}}{2}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.1559, size = 231, normalized size = 2.6 \begin{align*} -\frac{4 \, c^{2} \cos \left (b x + a\right )^{2} - \frac{8 \, a c d \cos \left (b x + a\right )^{2}}{b} + \frac{4 \, a^{2} d^{2} \cos \left (b x + a\right )^{2}}{b^{2}} + \frac{2 \,{\left (2 \,{\left (b x + a\right )} \cos \left (2 \, b x + 2 \, a\right ) - \sin \left (2 \, b x + 2 \, a\right )\right )} c d}{b} - \frac{2 \,{\left (2 \,{\left (b x + a\right )} \cos \left (2 \, b x + 2 \, a\right ) - \sin \left (2 \, b x + 2 \, a\right )\right )} a d^{2}}{b^{2}} + \frac{{\left ({\left (2 \,{\left (b x + a\right )}^{2} - 1\right )} \cos \left (2 \, b x + 2 \, a\right ) - 2 \,{\left (b x + a\right )} \sin \left (2 \, b x + 2 \, a\right )\right )} d^{2}}{b^{2}}}{8 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.474177, size = 203, normalized size = 2.28 \begin{align*} \frac{b^{2} d^{2} x^{2} + 2 \, b^{2} c d x -{\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (b x + a\right )^{2} + 2 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right )}{4 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.37364, size = 175, normalized size = 1.97 \begin{align*} \begin{cases} \frac{c^{2} \sin ^{2}{\left (a + b x \right )}}{2 b} + \frac{c d x \sin ^{2}{\left (a + b x \right )}}{2 b} - \frac{c d x \cos ^{2}{\left (a + b x \right )}}{2 b} + \frac{d^{2} x^{2} \sin ^{2}{\left (a + b x \right )}}{4 b} - \frac{d^{2} x^{2} \cos ^{2}{\left (a + b x \right )}}{4 b} + \frac{c d \sin{\left (a + b x \right )} \cos{\left (a + b x \right )}}{2 b^{2}} + \frac{d^{2} x \sin{\left (a + b x \right )} \cos{\left (a + b x \right )}}{2 b^{2}} - \frac{d^{2} \sin ^{2}{\left (a + b x \right )}}{4 b^{3}} & \text{for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac{d^{2} x^{3}}{3}\right ) \sin{\left (a \right )} \cos{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12213, size = 99, normalized size = 1.11 \begin{align*} -\frac{{\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (2 \, b x + 2 \, a\right )}{8 \, b^{3}} + \frac{{\left (b d^{2} x + b c d\right )} \sin \left (2 \, b x + 2 \, a\right )}{4 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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